In these notes, I consider to be a finite group.
Here we consider the base field of all the representations to be since it is algebraically closed, though any other algebraically closed field would work too, if you are careful about characteristics.
Finite abelian groups
Let be a finite abelian group.
Then has exactly many simple modules.
Proof
Since is abelian, is commutative.
Therefore, using the decomposition from the Artin-Wedderburn theorem, we have that , since each of the matrices have to be commutative.
This also gives that since the number of conjugacy classes of is .
Number of 1-dimensional representations
Let have commutator subgroup.
Then has exactly 1-dimensional representations.
Proof
is abelian, so any group homomorphism factors through .
That is