is non-injective if and only if , in which case there exists a unique monic irreducible polynomial of degree , (call it ) such that
moreover, is the minimal polynomial (polynomial of least degree which satisfies ).
Proof
Part 1
Say
Since is a field, the only non-unit is , so thus every unit in is mapped to a unit in under , therefore the universal property of fraction fields applies, and we have the following diagram
From this diagram, we can see that is injective and both and (which contains all generators of ) are in the image of .
Therefore, is an isomorphism of fields, which is .
This gives
On the right hand side, is all rational functions of which is a subspace and since is a basis.
Therefore, .
We know that is a field, so it is also an integral domain, therefore is also an integral domain.
This implies is a prime ideal.
is a PID, which means that for some monic polynomial (we can assume is monic because is a field) which vanishes on .
Since is prime, then it is also irreducible.
This gives the isomorphism
We can follow the implications
is then a subfield of that contains and so .
Note that when the degree of is since it has a basis of .
Lastly, we know that is minimal since by definition so and since this ideal is principal so by the division algorithm there is none of smaller degree.
Importance of theorem
Simple extensions are (in some way) concrete.
They are either quotients of polynomial rings (by some specific polynomial) or they are fraction field which are rational functions.
Both of these constructions are more understandable than general fields.