Let and be extensions.
Then is finite if and only if and are finite, and in this case
Proof
Assume is finite.
Then as a vector space over is finite dimensional.
From this, is a vector subspace then is finite (subspaces have same dimension or less).
Thinking of as a vector space, assume for contradiction that is infinite dimensional.
Then is infinite set of linear independent vectors.
But is finite dimensional (as a vector space over ) so there exists a linear relationship
so the let cannot be linear independent.
Assume now that and are finite.
Since they are finite dimensional subspaces, we can choose basis and respectively.
Take the candidate basis .
is spanning:
An arbitrary element can be written as