For a finite dimensional Lie algebra, the unique solveableideal containing all solvable ideals in is called the radical of .
It is often denoted .
Existence
If is a finite dimension Lie algebra, then exists.
Proof
Let be a solvable ideal of with maximal dimension.
Claim: if and are solvable ideals of , then is solvable.
Subproof: Consider the Lie (sub)algebra . Then is a solvable ideal of .
By the second isomorphism theorem, we have
So since and are solvable, then is solvable.
Solvability is preserved under extension, so is solvable as well.
Therefore, consider a solvable ideal such that .
Then is solvable with dimension larger than which contradicts the maximality of .
Therefore, for all solvable ideals .